How to get length of Integer in Pyramid using Deform

Question

This might be a silly question, but how would I get the length of a number using deform?

I have the following:

class BankingDetails(colander.MappingSchema):
    """ Deform class to add an Agent's Banking Details """
    account_number = colander.SchemaNode(
        colander.Integer(),
        validator=colander.Range(13),
        missing=None,
        widget=deform.widget.TextInputWidget(size=60))

    bank_name = colander.SchemaNode(
        colander.String(),
        validator=colander.Length(max=100, min=3),
        missing=unicode(''),
        widget=deform.widget.TextInputWidget(size=60))

    branch_code = colander.SchemaNode(
        colander.Integer(),
        validator=colander.Range(6),
        missing=None,
        widget=deform.widget.TextInputWidget(size=60))

I though that

validator=colander.Range(13),

would do it, but that only sets the minimum value.

I thought range() would work as the python method returns a list congaing e.g. 13 entries. obviously I was wrong.

Is there a way for me to get the Integer's length using pyramid deform?

Answer 1

Use Range(max=10 ** 13) (see the package documentation).

As mentioned by Sascha Gottfried below, you can use the min_err and max_err keyword arguments to set a custom error message.