Question

i'm got error what is this problem? how i get echo getAddress ?i'm tried eny time to fix that?

function getAddress($la, $lo){
  $ur= "http://maps.googleapis.com/maps/api/place/nearbysearch/json?location=".$la.",".$lo."&radius=10&sensor=true&key=AIzaSyA0JD_Z2Uo2AfnDTejQFWHAXOIaRRpjF8c"
   $json = file_get_contents($ur);

   $data = json_decode($json);
   $status = $data->status;
   $name= '';
     if($status == "OK"){
      $addr = $data->results[0]->formatted_address;
     }
   return $addr;
  } 
          echo getAddress("6.154841","80.700845");
Was it helpful?

Solution

You forgot a semi colon ; at the end of $ur

$ur= "http://maps.googleapis.com/maps/api/place/nearbysearch/json? location=".$la.",".$lo."&radius=10&sensor=true&key=AIzaSyA0JD_Z2Uo2AfnDTejQFWHAXOIaRRpjF8c";

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