Question

I'm working on an email piping script that needs to save just the reply content and not the original quoted email. I'm using a mime parser class (http://www.phpclasses.org/package/3169-PHP-Decode-MIME-e-mail-messages.html) to get all the information that I need from the email:

Message ID: AANLkTimYRxMJwjLSdcDP5ksM=xxx@mail.gmail.com
Reply ID: 20110316205225.xxx@example.com

Subject: Re: MessageX
To:  q1-1234567890@example.com
From: Someone someone@someothersite.com

Body: Hello,
Blah Blah Blah
-Someone

On Wed, Mar 16, 2011 at 3:52 PM,  <q1-1234567890@example.com> wrote:
> Hello,
>
> Some other blah, blah, blah.
>
> Thank you,
> Me

In the body section, I'm getting the original quoted email. How can I filter this out? I know email clients often add ">" next to quoted content, but I'm not sure if this would be good enough. Thanks for your help.

Was it helpful?

Solution

This might be doable with a regular expression. Try:

$text = preg_replace('#(^\w.+:\n)?(^>.*(\n|$))+#mi', "", $text);
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