Loop for string entry and reversal

Question

I am trying to receive a string, cut off the first letter, place it at the end of the string, and compare it to the original input. For some words it works and others it does not. I am not sure if this is a problem with the loop or what?

import java.util.*;
    public class Palin{

        public static void main(String args[])
        {
          String original,input;
          Scanner sc=new Scanner(System.in);

          System.out.println("Enter word and I will tell you if it has the property of a palindrome: ");
          original = sc.nextLine();
          char firstLetter = original.charAt(0);
          input = original.substring(1);
          input = input + firstLetter;
          StringBuilder input2=new StringBuilder(input).reverse();
          String s2=new String(input2);

          do{

            if(original.equals(s2))
                System.out.println(original + " is a Palindrome");
            else
                System.out.println(original + " is not a Palindrome");
                System.out.println("Enter another word. Or enter \"quit\" to end");
                original = sc.nextLine();
            } while (!(original.equalsIgnoreCase("quit")));

       }

}

Answer 1

I think I just had to cleanup references and location of the do-while. Thanks for the help.!

Output

Enter word and I will tell you if it has the property of a palindrome: Palindrome Palindrome does not have a Palindrome property Enter another word. Or enter "quit" to end uneven uneven has a Palindrome property Enter another word. Or enter "quit" to end banana banana has a Palindrome property Enter another word. Or enter "quit" to end dresser dresser has a Palindrome property Enter another word. Or enter "quit" to end quit

Revised code below.

import java.util.*; public class Palin{

        public static void main(String args[])
        {
          String original,input;
          Scanner sc=new Scanner(System.in);

          System.out.println("Enter word and I will tell you if it has the property of a      palindrome: ");
          original = sc.nextLine();

        do{

          char firstLetter = original.charAt(0);
          input = original.substring(1);
          input = input + firstLetter;

          StringBuilder input2=new StringBuilder(input).reverse();
          String s2=new String(input2);



            if(original.equals(s2))
                System.out.println(original + " has a Palindrome property");
            else
                System.out.println(original + " does not have a Palindrome property");
                System.out.println("Enter another word. Or enter \"quit\" to end");
                original = sc.nextLine();
            } while (!(original.equalsIgnoreCase("quit")));

       }

}

Answer 2

If you want to check only String is palindrome or not you can try something like:

    System.out.println("Enter String");
    Scanner s = new Scanner(System.in);
    String str = s.nextLine();
    StringBuilder sb = new StringBuilder(str);
    String rev = sb.reverse().toString();
    System.out.println(rev);
    if(str.equals(rev)){
        System.out.println("equal");
    }else{
        System.out.println("not equal");
    }

for the case sensitivity of string use String API.