The answer is no because the logistic function is non-linear: 1/(1+exp(-a)) + 1/(1+exp(-b))
is not equal to 1/(1+exp(-(a+b)))
.
But the inverse of the logistic function (also called log-odds), is linear (g(x)
in this wiki page). If you are calculating the log-odds, you can average the corresponding coefficients (beta0
and beta1
in the page) in your bagging procedure.