For a D-latch you want that data_out=data_in as long as enable is '1'. So if data_in changes while enable remains '1', data_out has to change. If data_in where not in the sensitivity list, this would not happen.
Question
Code from here: http://esd.cs.ucr.edu/labs/tutorial/latch.vhd
--------------------------------------------
-- Simple D Latch (ESD book Chapter 2.3.1)
-- by Weijun Zhang, 04/2001
--
-- latch is simply controlled by enable bit
-- but has nothing to do with clock signal
-- notice this difference from flip-flops
--------------------------------------------
library ieee ;
use ieee.std_logic_1164.all;
entity D_latch is
port( data_in: in std_logic;
enable: in std_logic;
data_out: out std_logic
);
end D_latch;
architecture behv of D_latch is
begin
-- compare this to D flipflop
process(data_in, enable)
begin
if (enable='1') then
-- no clock signal here
data_out <= data_in;
end if;
end process;
end behv;
Why does the "data_in" need to be in the sensitivity list? I know the process needs it for assignment however the process functions based on the enable input.
Thanks
Solution
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