I'm using suds to make SOAP requests to a third-party API.
import suds.client
client = suds.client.Client(WSDL_URL, location=SERVICE_URL)
When I try to create an object for a particular type defined by the WSDL (say TheObject
):
obj = client.factory.create('TheObject')
I'm getting an error about it not existing:
(TheObject) not-found
path: "TheObject", not-found
Traceback (most recent call last):
File "suds_test.py", line 67, in <module>
sys.exit(main(sys.argv))
File "suds_test.py", line 51, in main
obj = client.factory.create('TheObject'),
File "/usr/local/lib/python2.7/dist-packages/suds/client.py", line 234, in create
raise TypeNotFound(name)
suds.TypeNotFound: Type not found: 'TheObject'
So I print the list of available suds factory types with print(client)
:
Suds ( https://fedorahosted.org/suds/ ) version: 0.4 GA build: R699-20100913
Service ( OrderService ) tns="http://api.example.com/services/"
Prefixes (2)
ns0 = "http://api.example.com/contracts/stuff"
ns1 = "http://api.example.com/services/"
Ports (2):
(OrderServiceSoap)
Methods (123):
... Not really relevant
Types (123):
SomeType
SomeType2
ns0:AnotherType
ns0:AnotherType2
ns0:TheObject
...
So it appears that ns1
is the default namespace, and ns0
is the namespace I want to use for TheObject
. If I prefix it with the namespace alias it works.
obj = client.factory.create('ns0:TheObject')
I would prefer not to have to remember to use ns0
in this particular case because its vary arbitrary. I looked up the docs for Factory.create()
but it only accepts a single argument name with no additional arguments for namespace URL or anything.
Is there a way to dynamically determine the namespace for TheObject
? Or is it possible to specify the whole URL for ns0
instead of just the namespace alias? Any help would be appreciated.