You're returning a boolean with this line you defined RETURN ISNULL(@strAlphaNumeric,0)
. You must return a VARCHAR instead if this is really what you are trying to implement. Try changing your RETURNS VARCHAR(256)
with RETURNS TINYINT(1)
and see if this will work.
parsing string into int on mysql server by phpmyadmin
-
12-10-2022 - |
Question
I find this function
CREATE FUNCTION dbo.udf_GetNumeric
(@strAlphaNumeric VARCHAR(256))
RETURNS VARCHAR(256)
AS
BEGIN
DECLARE @intAlpha INT
SET @intAlpha = PATINDEX('%[^0-9]%', @strAlphaNumeric)
BEGIN
WHILE @intAlpha > 0
BEGIN
SET @strAlphaNumeric = STUFF(@strAlphaNumeric, @intAlpha, 1, '' )
SET @intAlpha = PATINDEX('%[^0-9]%', @strAlphaNumeric )
END
END
RETURN ISNULL(@strAlphaNumeric,0)
END
GO
and I want to use it, but i got an error like
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '@strAlphaNumeric VARCHAR(256)) RETURNS VARCHAR(256) AS BEGIN DECLARE @intAlp' at line 2
my version of phpmyadmin is 4.0.10
No correct solution
OTHER TIPS
Licensed under: CC-BY-SA with attribution
Not affiliated with StackOverflow