python social auth duplicate entry

Question

I'm using python-social-auth with django. I want to authorize via facebook, but before, I already registered in default way (email, password) with email that facebook use. Can I associate facebook account with registered account? I tried to search, but nothing

Answer 1

Check Associate users by email, that should explain how to do it.

Associate users by email

Sometimes it’s desirable that social accounts are automatically associated if the email already matches a user account.

For example, if a user signed up with his Facebook account, then logged out and next time tries to use Google OAuth2 to login, it could be nice (if both social sites have the same email address configured) that the user gets into his initial account created by Facebook backend.

This scenario is possible by enabling the associate_by_email pipeline function, like this:

SOCIAL_AUTH_PIPELINE = (
    'social_core.pipeline.social_auth.social_details',
    'social_core.pipeline.social_auth.social_uid',
    'social_core.pipeline.social_auth.auth_allowed',
    'social_core.pipeline.social_auth.social_user',
    'social_core.pipeline.user.get_username',
    'social_core.pipeline.social_auth.associate_by_email',  # <--- enable this one
    'social_core.pipeline.user.create_user',
    'social_core.pipeline.social_auth.associate_user',
    'social_core.pipeline.social_auth.load_extra_data',
    'social_core.pipeline.user.user_details',
)

This feature is disabled by default because it’s not 100% secure to automate this process with all the backends. Not all the providers will validate your email account and others users could take advantage of that.

Take for instance User A registered in your site with the email foo@bar.com. Then a malicious user registers into another provider that doesn’t validate his email with that same account. Finally this user will turn to your site (which supports that provider) and sign up to it, since the email is the same, the malicious user will take control over the User A account.

EDIT: Link fixed and copied docs details into this answer.