Opened Safari by pressing a button, how i can come back to my app

Question

I am new to iOS and objective C. I have to create a simple app where user will press a button and as a result, app will open safari. Then user have to come back to my app again. I have opened safari but I don't know how to bring user back to my app. I have used this simple code:

    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"http://www.google.com"]];

Any suggestion that how I can do that?

Answer 1

When you open a URL using

    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"http://www.google.com"]];

Your OS takes care of loading a new application. Instead if you wanna load a web URL use apple's UIWebView class.

Answer 2

I think you can't do this, only on your own urls following this:

First of all you want a custom scheme. https://coderwall.com/p/mtjaeq

[[UIApplication sharedApplication] openURL:[NSURL
URLWithString:@"http://www.yourserver.com/file.php"]];

Now because the url is point at your own server you can redirect using the scheme that you create eg. myapp://.

In your server, in file.php if you set this:

<script type="text/javascript">location.href="myapp://"</script>

Then will came back in your app.

Answer 3

If you can't control the page you are sending them to, no you can't do this.

If you want to remind them to come back, you could schedule a UILocalNotification to appear a few seconds after opening the URL - if they touch this they will be brought back into your app. This will pop up on screen as an alert or a banner depending on the current user preferences.