Can I use the OR operator in <xsl:value-of select>?

Question

I have been using the following piece of code to replace the regular expression '\s*AND\s*NOT\s*scope:\("TEXT"\)' with a specific string only if the match does not occurr (non-matching-substring):

<xsl:template name="strip-scopes">
                <xsl:param name="q" />
                <xsl:analyze-string select="$q" regex='\s*AND\s*NOT\s*scope:\("TEXT"\)'>
                        <xsl:matching-substring></xsl:matching-substring>
                        <xsl:non-matching-substring>
                   <xsl:value-of select="replace(replace(.,'AND \(scope:.*?\)',''), 'AND facet_.*?:\(.*?\)', '')"/>
                        </xsl:non-matching-substring>
                </xsl:analyze-string>
    </xsl:template>

It works fine, but I now need to include another condition in the <xsl:non-matching-string>. Is it possible to include an OR condition inside the element, so that both 'AND facet_.*?:\(.*?\)' and 'AND NOT facet_.*?:\(.*?\)' replacements can be allowed?

Answer 1

You can use replace(., 'foo|bar', 'whatever') to have both foo and/or bar substrings replaced with whatever. The second argument of replace is a regular expression and therefore | allows alternatives.