How to invoke pointer to member function when it's a class data member?
-
26-10-2019 - |
Question
struct B
{
void (B::*pf)(int, int); // data member
B () : pf(&B::foo) {}
void foo (int i, int j) { cout<<"foo(int, int)\n"; } // target method
};
int main ()
{
B obj;
// how to call foo() using obj.pf ?
}
In above test code, pf
is a data member of B
. What's the grammar rule to invoke it ? It should be straight forward, but I am not getting a proper match. e.g. If I try obj.*pf(0,0);
then I get:
error: must use ‘.*’ or ‘->*’ to call pointer-to-member function in ‘pf (...)’, e.g. ‘(... ->* pf) (...)’
Solution
Like this:
(obj.*obj.pf)(0, 1);
Member access (.
) has a higher precedence than a pointer to member operator so this is equivalent to:
(obj.*(obj.pf))(0, 1);
Because function call also has higher precedence than a pointer to member operator, you can't do:
obj.*obj.pf(0, 1) /* or */ obj.*(obj.pf)(0, 1)
As that would be equivalent to:
obj.*(obj.pf(0, 1)) // grammar expects obj.pf to be a callable returning a
// pointer to member
OTHER TIPS
pf is a method pointer, and you want to invoke the method it points to, so you have to use
(obj.*obj.pf)(1, 2);
It says the object obj you invoke the method pointed by pf
See result here :
The syntax is quite unnatural but a consequence of C++ precedence rules...
(obj.*obj.pf)(1, 2);
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