PHP if else while (with mysql) statement not working

Question

I have this piece of code in a function of mine that echos "Empty" if it cannot grab the data stored in the variable $result. The "Empty" part works fine. However, it will not echo the users data if the conditional enters the else part, why?

$result = mysql_query("SELECT * FROM `users` ORDER BY `earnings` DESC LIMIT ".$load.",1") or die (mysql_error());
if(!mysql_fetch_row($result)) {
    echo "Empty";
} else {
    while($data = mysql_fetch_array($result))
    {
        if($name == true) {
            echo ucfirst($data['user']);
        } else {
            echo ucfirst($data['earnings']);
        }
    }
}

Answer 1

By calling mysql_fetch_row($result) as a test, you are missing the first row of your data always. Check if number of rows is 0 instead.

Answer 2

HI I think you issue is in mysql_fetch_array(). This function will return array not associative array..

you can use

$result = mysql_query("SELECT * FROM `users` ORDER BY `earnings` DESC LIMIT    ".$load.",1") or die (mysql_error());
if(mysql_num_rows($result) == 0) {
   echo "Empty";
} else {
     while($data = mysql_fetch_array($result,MYSQL_BOTH))
 {
    if($name == true) {
        echo ucfirst($data['user']);
    } else {
        echo ucfirst($data['earnings']);
    }
 }
}

Use mysql_num_rows intead of mysql_fetch_row to check empty recordset.

I pass the 2nd parameter in mysql_fetch_array which MYSQL_BOTH that will return both array and associative array..

Or you can use

mysql_fetch_assoc() function istead of mysql_fetch_array()..

Feel free to ask question..

Answer 3

try this

$result = mysql_query("SELECT * FROM `users` ORDER BY `earnings` DESC LIMIT ".$load.",1") or die (mysql_error());
    if(!$result) {
        echo "Empty";
    } else {
        while($data = mysql_fetch_array($result))
        {
            if($name == true) {
                echo ucfirst($data['user']);
            } else {
                echo ucfirst($data['earnings']);
            }
        }
    }