How to convert malformed list into a list of int in python [closed]

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Here is my list; an output from a database entered as string:

list_=(('[96, 71, 16, 81, 21, 56, 91]',),)

My goal is to convert it into a list of ints: [96, 71, 16, 81, 21, 56, 91]

My attempt:

import ast
print ast.literal_eval(list_[0][0])

The expected output

Output:[96, 71, 16, 81, 21, 56, 91]

However, the solution is not compatible with some of the output

list_[0][0]

results in an error: out of range.

Any suggestions on other possible methods to solving the problem? Thanks.

Answer 1

import ast
print ast.literal_eval([y for x in list_ for y in x][0])

Answer 2

while type(list_) is not str:
    try:
        list_ = list_[0]
    except IndexError:
        break

Now list_ is the string you want.

Answer 3

Have you tried this:

from numpy import fromstring
fromstring(list_[0][0][1:(len(list_[0][0])-1)], sep=',', dtype='int32').tolist()

Answer 4

And just for fun, a generic untangler

from collections import Iterable

def untangle(thing):
    stack = [thing]
    result = []
    while stack:
        current = stack.pop()
        if isinstance(current, basestring):
            if current[-1] == ']':
                current = current[1:-1]
            for x in current.strip().split(','):
                result.append(int(x.strip()))
        elif isinstance(current, Iterable):
            stack.extend(reversed(current))
        else:
            print "dont know what do do with", repr(current)
    return result

untangle((('[96, 71, 16, 81, 21, 56, 91]',),))
[96, 71, 16, 81, 21, 56, 91]