Get random element using XPath

Question

I need to get a random element of a specific result set. I have a working XPath expression and need the same thing in the other one. This is what i have right now:

The working one:

ad/item[[eval:('Math.floor(Math.random()*7)+1')]]

and this is the one I need. It needs also the random in but with the filter on recommended:

query/results/json/feed/entry[contains(gsx_type/_t,'recommended')]

I know that if i just want a number I can put it like this:

query/results/json/feed/entry[contains(gsx_type/_t,'recommended')][3]

or

query/results/json/feed/entry[(contains(gsx_type/_t,'recommended')) AND (item = 3) ]

But this is not what I need. I have 12 pictures that are recommended so maybe if someone knows what to write to make this work that would be really great!

Answer 1

If I understood you correctly what you want to achieve, you can simply combine both:

query/results/json/feed/entry[contains(gsx_type/_t,'recommended')][eval:('Math.floor(Math.random()*7)+1')]

However, this eval:() function looks very strange to me, you might also be able to use a random module provided by your processor or call a functions differently. Also, if you have 12 pictures you might want to change the 7 to 12.