Outputting a randomly filled array list multiple times with different results each time?

Question

So im filling an array with random numbers from 1-10 by using a second array to fetch the numbers from. I need to get 10 different results, each run outputting a different random array list. How could i do that? Right now if i try to output it more than once, it just out puts the same numbers over and over again. I need 10 different outputs.

public static void main(String[] args) {
    List<Integer> numbers =new ArrayList<Integer>();
    List<Integer> numbers2 =new ArrayList<Integer>();

    Random generator = new Random();


    for(int i = 0; i<=10;i++) {
        numbers2.add(i);
    }

   for(int z = 0; z<=10; z++){

    for(int i = 0; i<=1000;i++) {

        int x = generator.nextInt(10)+1;
        if (!numbers.contains((numbers2.get(x)))) {
            numbers.add(numbers2.get(x));;
        }
    }
    System.out.println(numbers);
}

}

Answer 1

You are using the same numbers array at each of the 10 iterations. By the time the first iteration is over, the array already has every digit from 1 to 10 so the if condition will evaluate to false and nothing will be added to it.

So you need to create a new numbers array for each of the 10 iterations, or remove its contents after printing it.