Question

I am trying to retrieve the photo of a contact using Google Contacts API according to this document. The PHP Client library used is here. I get the code and user information successfully but failed to get the user's photo data.

The response I got is :

Photo query failed - invalid contact ID

.

This is the PHP code of the callback function that I'm using to get the user's photo data :

$client = new Google_Client();

$client->setClientId(GOOGLE_APP_CLIENT_ID);
$client->setClientSecret(GOOGLE_APP_CLIENT_SECRET);
$client->setRedirectUri(GOOGLE_APP_CLIENT_REDIRECT_URI);
$client->addScope("openid profile email https://www.google.com/m8/feeds");

// Create a OAuth 2 service instance
$oauth2 = new Google_Service_Oauth2($client);

// Get the access token using code.
if (isset($_GET['code'])) {
    // Authenticate the code
    $client->authenticate($_GET['code']);
    $_SESSION['access_code'] = $client->getAccessToken();
    
    // Set the access token
    $client->setAccessToken($_SESSION['access_token']);
    $temp_obj = $client->verifyIdToken();
    ....
    // Get the user's info
    $guser_info = $oauth2->userinfo->get();
    // Get the contact id
    $contact_id = $guser_info['id'];
    // Get the user email
    $user_email = $guser_info['email'];
    
    // Make an authenticated request to the photo
    $req = new Google_Http_Request("https://www.google.com/m8/feeds/photos/media/default/$contact_id");
    // For replacing above line with the following also got the same result.
    //$req = new Google_Http_Request("https://www.google.com/m8/feeds/photos/media/$user_email/$contact_id");
    
    // Make an authenticated request
    $val = $client->getAuth()->authenticatedRequest($req);
    
    print_r($val->getResponseBody());// Get "Photo query failed - invalid contact ID"
} ...

I have enabled Contacts API in the console project and added scope https://www.google.com/m8/feeds.

Is the retrieved id different from Contact ID of the user or is there a way to get the user's Contact ID or something wrong in my code?
Any help or comments are appreciated.

Was it helpful?

Solution

I am using Hybridauth with a similar code to get the user profile image (laravel style):

<?php
//@see http://www.mrcasual.com/on/coding/laravel4-package-management-with-composer/
public function getSocial($action = '')
{
    // check URL segment
    if ($action == 'auth') {
        // process authentication
        try {
            Hybrid_Endpoint::process();
        }
        catch (Exception $e) {
            // redirect back to http://URL/social/
            return Redirect::to('login/social');
        }
        return;
    }
    try {
        // create a HybridAuth object
        $socialAuth = new Hybrid_Auth(app_path() . '/config/hybridauth.php');
        // authenticate with provider
        if($action != ''){
            if(in_array($action,array('google'))){
                $provider = $socialAuth->authenticate($action);
            }else{
                return Redirect::to('login');
            }
        }else{
            return Redirect::to('login');
        }
        // fetch user profile
        $userProfile = $provider->getUserProfile();
    }
    catch(Exception $e) {
        // exception codes can be found on HybBridAuth's web site
        return Redirect::to('login');
    }
    access user profile data
    echo "Connected with: <b>{$provider->id}</b><br />";
    echo "As: <b>{$userProfile->displayName}</b><br />";
    echo "<pre>" . print_r( $userProfile, true ) . "</pre><br />";
    echo "PhotoURL: {$userProfile->photoUrl}<br />";
    die();
}

Maybe your $guser_info already contains a link to the photo? Did you try to print_r it?

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