Most likely, it's because of how you are combining the artikelnummer
and the auspraegungID
.
I do not think you have accounted for that fact that '100' + '0'
is idential to '10' + '00'
.
Instead of trying to merge two fields into one, perhaps try the following?
SELECT
*
FROM
#allArticles AS allArticles
WHERE
Artikelnummer = 'IT-810260'
AND NOT EXISTS (SELECT *
FROM KHKPreisListenArtikel
WHERE ListeID = 4
AND Artikelnummer = allArticles.Artikelnummer
AND Auspraegung = allArticles.Auspraegung
)
If that still doesn't work, then you must have corresponding records in that other table, find them like this...
SELECT
*
FROM
#allArticles AS allArticles
INNER JOIN
KHKPreisListenArtikel AS Preis
ON Preis.ListeID = 4
AND Preis.Artikelnummer = allArticles.Artikelnummer
AND Preis.Auspraegung = allArticles.Auspraegung
WHERe
allArticles.Artikelnummer = 'IT-810260'
PLEASE ALSO NOTE
Please don't include images of code, please copy the code, so that we can copy it too.
Especially when the tables/fields are in another language...
EDIT
Here is a query that will show the cause of your original query to fail.
SELECT
*
FROM
#allArticles AS allArticles
INNER JOIN
KHKPreisListenArtikel AS Preis
ON Preis.ListeID = 4
AND Preis.Artikelnummer + CONVERT(VARCHAR(50), Preis.Auspraegung)
=
allArticles.Artikelnummer + CONVERT(VARCHAR(50), allArticles.Auspraegung)
WHERE
allArticles.Artikelnummer = 'IT-810260'