If I'm not mistaken, you want random points on a spherical manifold with a gaussian distribution of distances from the center. If so, then you have the latter problem solved by sampling gaussian values of the radius using numpy.rand.normal
To get random spherical points is a little bit more tricky, but here's some code to do it (and a description of the math behind it at Wolfram MathWorld):
import numpy as np
num_points = 500
U = np.random.random(num_points)
V = np.random.random(num_points)
import math as m
def spherical_to_cartesian(vec):
'''
Convert spherical polar coordinates to cartesian coordinates:
See the definition of spherical_cartesian_to_polar.
@param vec: A vector of the 3 polar coordinates (r, u, v)
@return: (x, y, z)
'''
(r, u, v) = vec
x = r * m.sin(u) * m.cos(v)
y = r * m.sin(u) * m.sin(v)
z = r * m.cos(u)
return [x, y, z]
radius = 1.
points = np.array([spherical_to_cartesian([radius, 2 * np.pi * u, np.arccos(2*v - 1)]) for u,v in zip(U,V)])
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
fig, ax = plt.subplots()
ax = Axes3D(fig)
ax.plot(points[:,0], points[:,1], points[:,2], 'o')
Which will give you points like this:
Now if you want them to have normally distributed radii, you just need to substitute your randomly generated values in the list comprehension which uses the variable radius like this:
radii = np.random.normal(10, 3, 100)
points = np.array([spherical_to_cartesian([r, 2 * np.pi * u, np.arccos(2*v - 1)]) for r,u,v in zip(radii, U,V)])
Is this more or less what you're looking for?