when n=3, it gives me a bad file error at error 5.
This could be fixed by removing that if(close(p[i][1]<0)){
in your code, because you need to read from p[i][0]
in your last iteration, i.e.
if (i == n) {
if(read(p[n-1][0],&result,sizeof(result)<0)){
...
}
}
This is an implementation of your idea, I hope it may be helpful:
#include <sys/types.h>
#include <sys/wait.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int
main(int argc, char *argv[])
{
if (argc != 2) {
fprintf(stderr, "Usage: %s N\n", argv[0]);
exit(EXIT_FAILURE);
}
int n = atoi(argv[1]);
int pipes[n][2];
int i, val;
pid_t pid;
val = 0;
for (i = 0; i < n; i++) {
if (pipe(pipes[i]) < 0) {
perror("pipe");
exit(EXIT_FAILURE);
}
if ((pid = fork()) < 0) {
perror("fork");
exit(EXIT_FAILURE);
}
else if (pid == 0) {
close(pipes[i][1]);
if (read(pipes[i][0], &val, sizeof(val)) != sizeof(val)) {
perror("read");
exit(EXIT_FAILURE);
}
printf("C %d read %d\n", getpid(), val);
val++;
}
else {
close(pipes[i][0]);
printf("P %d writes %d\n", getpid(), val);
if (write(pipes[i][1], &val, sizeof(val)) != sizeof(val)) {
perror("write");
exit(EXIT_FAILURE);
}
if (waitpid(pid, NULL, 0) != pid) {
perror("waitpid");
exit(EXIT_FAILURE);
}
printf("%d is going to leave.\n", getpid());
exit(EXIT_SUCCESS);
}
}
printf("%d is going to leave.\n", getpid());
exit(EXIT_SUCCESS);
}
Testing run:
$ ./a.out 3
P 2005 writes 0
C 2006 read 0
P 2006 writes 1
C 2007 read 1
P 2007 writes 2
C 2008 read 2
2008 is going to leave.
2007 is going to leave.
2006 is going to leave.
2005 is going to leave.
Explanation:
The frame of that code is for (i = 0; i < n; i++) { pipe(); fork(); }
, which means it will create n
pipes, and n
new processes. In each iteration, the parent will write to pipes[i][1]
and child will read from pipes[i][0]
. Eventually, it will create a process chain connected by a series of pipes, and a value is passed down from the first process to the last through that series of pipes.