Couting combinations within a group

Question

I need a way way to count combinations of code by patients, so I need to know based on this report total duration of each Service Program Protocol, so based on the picture below I need it to be like this

Patient: 00000036

Adult CSS IND 240

Adult OP IND 120

Patient: 00000040

Adult CSS IND 420

Adult OP IND 60

I am using Microsoft SQL Server 2005 and I would prefer a fix in SQL, but if it could be done in crystal I could work with that. Thank you in advance.

select 

pct.patient_id,
pct.clinic_id,
pct.service_id,
pct.program_id,
pct.protocol_id,
pct.proc_duration


from patient_clin_tran pct
join patient p
on pct.patient_id = p.patient_id and pct.episode_id = p.episode_id
join patient_custom pc
on pct.patient_id = pc.patient_id
join staff s
on pct.attending_id = s.staff_id
where pc.health_home = 'Y'
group by pct.patient_id, pct.clinic_id, pct.service_id, pct.program_id, pct.protocol_id, pct.proc_duration
order by pct.patient_id, pct.clinic_id, pct.service_id, pct.protocol_id

Answer 1

You were close. You do need the GROUP BY, but you do not want to GROUP BY the duration column. Instead you want to use the SUM function in the SELECT list on your proc_duration column:

select 
   pct.patient_id,
   pct.clinic_id,
   pct.service_id,
   pct.program_id,
   pct.protocol_id,
   SUM(pct.proc_duration) AS [Total Duration]  

FROM patient_clin_tran pct
  join patient p
  on pct.patient_id = p.patient_id and pct.episode_id = p.episode_id

  join patient_custom pc
  on pct.patient_id = pc.patient_id

  join staff s
  on pct.attending_id = s.staff_id

where pc.health_home = 'Y'
group by pct.patient_id, pct.clinic_id, pct.service_id, pct.program_id, pct.protocol_id
order by pct.patient_id, pct.clinic_id, pct.service_id, pct.program_id, pct.protocol_id