Search in python tuple list

Question

db = [('cat',15,22),('dog',28,30),('human',27,80)]

Now I want to create search for 'dog' so my returned value will be db[1]. I can't still figure it out (I know I would use sth like for item in db: if 'dog' in item[:] but don't know how to put it together really.

Please help?

Answer 1

items = [i for i in db if 'dog' in i]
items[0] if items else None
# ('dog', 28, 30)

Answer 2

If you're looking for the first item that matches (as suggested by you saying that your returned value should be db[1]) then you can use

next((x for x in db if x[0] == 'dog'), None)

In case 'dog' may be in any element of the tuple - so that (28, 'dog', 30) would also be matched - I'd go with

next((x for x in db if 'dog' in x), None)

See the answers to find first element in a sequence that matches a predicate for how this works.

Answer 3

You can use filter:

filter(lambda x:'dog' in x, db)

Output:

[('dog', 28, 30)]

Answer 4

You mean this?

f = lambda db,x: [_t for _t in db if _t[0]==x][0]

Output:

>>> f(db,'dog')
('dog', 28, 30)