PyQt4 : How can i toggle the “Stay On Top” behavior?

Question

I want to create an app, where the user will decide it the main window will stay always on top of the other apps.

In PyQt4 it is easy to create a window that will stay always on top. This is covered here : PyQt: Always on top

What I want to have a widget (menu item, checkbox etc) that will toggle this behavior on or off. So far i haven't found a way to reset the original behavior.

thank you

UPDATE After the suggestion of İsmail 'cartman' Dönmez, I searched a bit more and I found an implementation of the WindowFlags example in PyQt4.

It can be found here

Answer 1

This should disable it:

window.setWindowFlags(window.windowFlags() & ~QtCore.Qt.WindowStaysOnTopHint)

This should enable it:

window.setWindowFlags(window.windowFlags() | QtCore.Qt.WindowStaysOnTopHint)

Answer 2

You want the Qt::WindowStaysOnTopHint hint, see Window Flags Example.

Answer 3

Rosh is correct. But don't forget to include window.show() after you change the flag. Your window will be hidden when the flag is changed. I have also included the code for toggling the flag.

This will clear it:

window.setWindowFlags(window.windowFlags() & ~QtCore.Qt.WindowStaysOnTopHint)

This will enable it:

window.setWindowFlags(window.windowFlags() | QtCore.Qt.WindowStaysOnTopHint)

This will toggle it:

window.setWindowFlags(window.windowFlags() ^ QtCore.Qt.WindowStaysOnTopHint)

Answer 4

I'm not able to comment on Rosh's answer, so noting here - for PyQt 5.7 on Devuan, if you toggle the WindowStaysOnTopHint flag on a QDialog after it is shown, the window disappears and you need to show() it again immediately after. Other than this it works.