Use Double.doubleToRawLongBits(double)
, and then Long.toBinaryString(long)
on the result:
double d = 0.4;
System.out.println(Long.toBinaryString(Double.doubleToRawLongBits(d)));
Question
i search in this site and other for converting double value like .4 to binary but there is no useful answers ! i know the procedure multiply by 2 if the number is bigger than 1 save the 1 subtract it and more time multiply it by 2 and so on . help me !
double d = .4 ;
double e ;
while ()
{
e = d*2;
if (e>1) {
s[i]= 1;
e=d-1;
} else {
s[i] = 0;
}
System.out.print(s[i]);
}
Solution
Use Double.doubleToRawLongBits(double)
, and then Long.toBinaryString(long)
on the result:
double d = 0.4;
System.out.println(Long.toBinaryString(Double.doubleToRawLongBits(d)));