This non-linear system of ODEs is not easily solved analytically. You can try Mathematica if you have it (it tends to be better at symbolic math than MATLAB's MuPad):
DSolve[{a'(t) = -k*d(t)*a(t)*b(t)^2, b'(t) = -k*f(t)*b(t)*c(t)^2, c'(t) = k*d(t)*a(t)*b(t)^2 - k*e(t)*a(t)*d(t), d'(t) = k*d(t)*a(t)*b(t)^2, e'(t) = -k*e(t)*a(t)*d(t), f(t) = k*f(t)*b(t)*c(t)^2}, {a(t),b(t),c(t),d(t),e(t),f(t)}, t]
(I can't test this because the input is too long for the free version of Wolfram|Alpha :)
Anyway, it's easy to do it numerically in MATLAB:
function top
%// Initial values (random for this example)
y0 = 125*randn(6,1);
%// Time span to simulate
tspan = [0 +1];
%// Solve system numerically
[t,y] = ode45(@deriv, tspan, y0);
%// Make a nice plot
plot(t,y)
xlabel('t'), ylabel('function values')
legend('a(t)', 'b(t)', 'c(t)', 'd(t)', 'e(t)', 'f(t)')
end
function dydt = deriv(~,y)
%// Set the value for your 'k'
k = 1e-4;
%// rename the variables for clarity
[a,b,c,d,e,f] = deal(y(1),y(2),y(3),y(4),y(5),y(6));
%// Compute the derivative
dydt = k * [
-d*a*b^2
-f*b*c^2
+a*(d*b^2 - e*d)
+d*a*b^2
-e*a*d
+f*b*c^2
];
end
One of the funkier solutions I got with this:
Out of curiosity: what do these equations describe? I'd say concentrations of substances undergoing a chemical reaction, but it'd be pretty strange (for some initial values you'll find negative concentrations, singularities, etc., stuff you just wouldn't expect in such systems, so...my curiosity is triggered :)