Open a file in the directory Resources

Question

I want to open an included html file in the Resources directory, but it seems like my path is wrong or I am making some other mistake.

I am currently in a form class and I want to open the file if the user presses the button F1.

System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo.FileName = "f1.html";
proc.Start();

Answer 1

If you want to get some embedded resource, you need to call

ResourceManager.GetStream

http://msdn.microsoft.com/en-us/library/zxee5096.aspx

It will return a memory stream. Read the memory stream to a byte array and write the byte array to some temp location and then invoke

Process.Start()

using the path of the temp file as argument.

Here is a sample code:

public class Class1{
    public static void Main(string[] args){
        FileStream stream = null;
        string fullTempPath = null;
        try{
            byte[] page = Resources.HTMLPage1;
            fullTempPath = Path.GetTempPath() + Guid.NewGuid() + ".html";
            stream = new FileStream(fullTempPath, FileMode.Create, FileAccess.Write, FileShare.Read);
            stream.Write(page, 0, page.Length);
            stream.Flush(true);
            stream.Close();
            Process proc = new Process{StartInfo ={FileName = fullTempPath}};
            proc.Start();
        }
        finally{
            if (stream != null){
                stream.Dispose();
            }
        }
    }
}

Answer 2

Use this code to open an html file using the default browser

        string filename = Environment.CurrentDirectory + System.IO.Path.DirectorySeparatorChar + "f1.html";

        System.Diagnostics.Process.Start(filename);