Question

So i've update my code and im still stumped on how to check a 3x3 block within a completed sudoku board to see if it doesn't have any repeating numbers. this is my method that i've updated.

static boolean isBlock1Valid(int[][] sudokuBoard, int referenceRow, int referenceColumn)
{

    boolean[] seen = new boolean[9];

    for (int i = 0; i < 3; i++){

        for (int j = 0; j < 3; j++){

            if ( seen(sudokuBoard[referenceColumn+i][referenceRow+j])) return false;


    else ( seen(sudokuBoard[referenceColumn+i][referenceRow+j])) = true;
    }
    }
return true;
}//end of isBlock1Valid

this is the calling method i don't know which parametrs to send to the method isBlock1Valid

    public static void Validate(final int[][] sudokuBoard)
{
    int width = sudokuBoard[0].length;
    int height = sudokuBoard.length;

    for(int i = 0; i < width; i++)
        if(!IsValidRow(sudokuBoard, i, width))
        {
            System.out.print("Invalid entry found \n (Row)" + "\t"+ i + "\n");
          //Do something - The row has repetitions
        }
        else{
            System.out.print("Row " +i + " is valid \n");
        }
    for(int j = 0; j < height; j++)
        if(!IsValidColumn(sudokuBoard, j, height))
        {
            System.out.print("(Column)" + j + "\n");
          //Do something - The columns has repetitions
        }
        else{
            System.out.print("Column " +j +" is valid \n");
        }
   for(int i=0; i<2; i++)
        if(!IsBlock1Valid(sudokuBoard,i, j)){
            System.out.print("hi");
        }

}
Was it helpful?

Solution

Accessing a cell in an array should be using square brackets, and seen is an array:

seen[sudokuBoard[referenceColumn+i][referenceRow+j]]
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