How to count OR conditions which are "true" in a If loop and execute different code for different count results

Question

I have 5 different OR conditions in a If loop:

if(cond1 || cond2 || .... || cond5)

All conditions are bool type in C#

The problem is I have to execute certain code if any one condition is true, another code when any two conditions are true, another code when any three are true, another code when any four are true, another code when all are true and another code when none is true.

How do I solve the problem?

My approach is:

if(1 == (Convert.ToInt(cond1) + Convert.ToInt(cond2) + ... + Convert.ToInt(cond5)))
{
  //Code1
}
else if(2 == (Convert.ToInt(cond1) + Convert.ToInt(cond2) + ... + Convert.ToInt(cond5)))
{
  //Code2
}
.... and so on...

Is there any better approach?

Answer 1

int count =     
Convert.ToInt32(cond1)+Convert.ToInt32(cond1)+...+Convert.ToInt32(cond1);

switch(count)
{
    case 1:
    //your code here
    break;
    .
    .
    .
    case 5:
    //your code here
    break;
}

This might help you..