Question

First off : I'm using an azerty keyboard. I want to press the button which is in the upper left corner, just below 'escape'. I believe it's the '~' for qwerty keyboard (for azerty it is '²')

I unsuccesfully search for it's key code then I found this : java.awt.event.KeyEvent not capable of fully mappin AZERTY keyboard?

Running his code I got this :

Pressed : unknown keyCode: 0x0 / ² code = 0

By inspecting the keyEvent object while debugging I got this

extendedKeyCode = 16777394
keyLocation = 1
id = 401

How could I solve this problem? Do you think I could make my own Implementation of keyEvent, build one that is similar then raise it?

Thanks.

Was it helpful?

Solution

Well I just made a loop to press keyEvent from 0 to 10 000 000 and '²' was never pressed.

package keyCodeTester;

import java.awt.Robot;
import java.awt.event.KeyEvent;

public class KeyCodeTester {
    public static void main(String args[]) throws Exception {
        Robot robot = new Robot();
        robot.delay(5000);

        for(int i=41; i<10000000; i++) {
            try {
                if (i>=112 && i<=123) {
                    throw new IllegalArgumentException("touche fonction");
                }
                robot.keyPress(i);
                robot.delay(100);
                robot.keyPress(KeyEvent.VK_ENTER);
                robot.delay(100);
            } catch (IllegalArgumentException iae) {
                System.out.println("iae pour " + String.valueOf(i));
            }
        }

    }
}

I guess robot only works for qwerty. I'm going to make some C code and call it from java.

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