@echo off
setlocal ENABLEDELAYEDEXPANSION
for /f "tokens=1* delims=" %%i in (input.txt) do (
set _line=%%i
set _line=!_line:%%=%%%%!
echo !_line! >> output.txt
)
endlocal
Replace string % with %% using batch file
-
04-07-2023 - |
Question
I have a text like below in input.txt file.
sdf%5Ddfssdsd%2Ddfdf
I would like to replace "%" with "%%" in the output file. so the text should look like
sdf%%5Ddfssdsd%%2Ddfdf
Appreciate your help!!
Solution
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