Question

"Thus, the total time for Prim's algorithm is O(V lg V + E lg V) = O(E lg V), which is asymptotically the same as for our implementation of Kruskal's algorithm."

From http://serverbob.3x.ro/IA/DDU0137.html

But why is O(V lg V + E lg V) = O(E lg V) ??

Is it because E is at least V-1 ?

Was it helpful?

Solution

Because in the normal case we assume that E is larger than V. So by ignoring the lower order terms we got E lg V

OTHER TIPS

Specifically, E can be a maximum of V^2 in a directed graph. If we assume E = v^2 (to account for worst case), E swallows V.

Licensed under: CC-BY-SA with attribution
Not affiliated with StackOverflow
scroll top