I removed the IDs from the price DIVs, to get rid of duplicate IDs. I moved these IDs into the class, so that the same class can be used in prices for different products.. Then I used jQuery
to show only the prices whose class matches the currently selected radio button's ID.
HTML:
<div class="switch-toggle switch-5 switch-candy">
<input id="alusa" name="view" type="radio" checked>
<label for="alusa" onclick="">USA</label>
<input id="aluk" name="view" type="radio">
<label for="aluk" onclick="">UK</label>
<input id="alin" name="view" type="radio">
<label for="alin" onclick="">India</label>
<input id="altr" name="view" type="radio">
<label for="altr" onclick="">Turquia</label>
<input id="alhk" name="view" type="radio">
<label for="alhk" onclick="">Hong-Kong</label>
<a class="btn btn-primary"></a>
</div>
<div class="clearfix mar_top3"></div>
<div class="pricing-tables-two">
<div class="title">Economy</div>
<div class="price alusa">$3.99 <i>/ per month</i></div>
<div class="price aluk">$6.99 <i>/ per month</i></div>
<div class="cont-list">
<ul>
<li>Unlimited Bandwidth</li>
<li>100 GB Space</li>
<li>10 Databases</li>
<li>Ad Credits</li>
<li>1 Free Domain</li>
<li>24/7 Unlimited Support</li>
<li class="last">100 Email Addresses</li>
</ul>
</div>
<div class="ordernow"><a href="#" class="button darkgray small align">Order Now</a></div>
</div><!-- end section -->
JS:
$(function() {
$(".price:not(.alusa)").hide();
$(":radio[name=view]").change(function() {
$(".price").hide();
$(".price." + this.id).show();
});
});