SQL joins with order by

Question

I have two tables with

table 1
col1 date
1    13/4/2014
2    15/4/2014
3    17/4/2014
5    19/4/2014

table 2
col1 date
1    13/4/2014
3    16/4/2014
6    18/4/2014

joining the two tables i should get

col1 date       col2 date
1    13/4/2014  1    13/4/2014
2    15/4/2014
3    17/4/2014  3    16/4/2014
                6    18/4/2014
5    19/4/2014

the important thing is the date columns should be sorted as can be seen for col data 6 and 5. Is this possible?

EDIT : the final table needs to be ordered by col1.date and col2.date such that earlier date either in col1 or col2 will be sorted in the join table 18/4/2014 will come before 19/4/2014 even if they are in different columns. I hope i am making my point clear. Thanks EDIT :

table 1
1, "2014-04-03" 
2, "2014-04-04"
3, "2014-04-11"
4, "2014-04-16"
5, "2014-04-04"
6, "2014-04-17"
7, "2014-04-17"

table 2
1, "2014-04-04"
2, "2014-04-11"
5, "2014-04-17"

EDIT : after join it should be like

1 2014-04-03 
2 2014-04-04 
5 2014-04-04 1 2014-04-04
3 2014-04-11 2 2014-04-11
4 2014-04-16 
6 2014-04-17
7 2014-04-17 5 2014-04-17

Answer 1

select n.col1
     , n.date1
     , m.col2
     , m.date2
from t1 n 
full join t2 m on n.date1 = m.date2
              and n.col1 = (select max(col1) from t1 where date1 = m.date2 )  
              and n.col1 is not null
where n.date1 is not null or m.date2 is not null
order by coalesce(n.date1, m.date2)
       , coalesce(n.col1, m.col2)

SQLFiddle with new data

SQLFiddle with old data

Answer 2

SQL Fiddle

select col1, date1, col2, date2
from
    t1
    full outer join
    t2 on col1 = col2
order by coalesce(date1, date2), date2;

Answer 3

Thankfully, PostgeSQL has a wonderful function called LEAST(); the query is then simply:

SELECT col1, date1, col2, date2
FROM t1
FULL OUTER JOIN t2
             ON col1 = col2
ORDER BY LEAST(date1, date2), GREATEST(date1, date2)

(fiddle for dataset 1, fiddle for dataset 2).

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EDITED

Added use of GREATEST() to then sort by the other value.