Switch in a for loop

Question

I was writing a java program that had a switch in a for loop, and the switch wouldn't loop. the code read as follows:

import static java.lang.System.out;
import java.util.Scanner;

public class Translate {


    public static void main(String[] args) {
        Scanner keyboard = new Scanner(System.in);
        String input=null;
        int i;
        char letter;
            do{             
                out.print("Enter a word to translate");
                input=keyboard.next();
            } while(input==null);
            out.println(" ");//blank line, aesthetics.
            for (i=0;i==input.length();i++);//the misbehaving loop{
                letter=input.charAt(i);
                switch(letter){
                case 'a':{
                    out.print("(-)");
                    break;
                }case 'b':{ 
                    out.print("(-|)");
                    break;
                }case 'c':{
                    out.print("(-\\)");
                    break;
                }case 'd':{
                    out.print("(|--)");
                    break;
                }case 'e':{
                    out.print("(|||)");
                    break;
                }case 'f':{
                    out.print("(|-)");
                    break;
                }default:{
                    out.print("GOODBYE");
                }
            }
        }
       }
 }

Answer 1

there are 2 mistakes in this

for (i=0;i==input.length();i++);//the misbehaving loop{

1. i==input.length() should be i<input.length()
2. there should not be ; after for loop

for (i=0;i==input.length();i++); should be for (i=0;i<input.length();i++)

Answer 2

The loop is misbehaving because the switch statement is not the part of the for loop. The loop is terminating right where it is declared. This is because of the ; next to the for-loop.