How to match digits in perl glob

Question

$dir_path = (-d ("./abc/dir-\d.\d.\d")) ?
            glob("./abc/dir-\d.\d.\d/my-dir*") : "my-dir-doesnot-exists";

is this a valid glob option? can I use \d to match numbers in the dir path ?

$dir_path should get "./abc/dir-#.#.#/my-dir/some_dir_name" if "./abc/dir-#.#.#" exists (where # is any digit) else "my-dir-doesnot-exists" string

Answer 1

You're calling both instances of glob in scalar context (but not as an iterator) which is very wrong. For example,

 my $foo = glob("a");
 my $bar = glob("a");
 say $foo // "[undef]";    # a
 say $bar // "[undef]";    # [undef]

The glob language is completely different than the regex language. \d won't work, but [0123456789] would.

my @dir_paths = glob("./abc/dir-[0123456789].[0123456789].[0123456789]/my-dir*");

die "No match!"         if !@dir_paths;
die "Too many matches!" if @dir_paths > 1;

my $dir_path = $dir_paths[0];