Array to string conversion error in Radio

Question

$data = mysql_query(" SELECT * FROM user_pokemon_db WHERE user_id = '".$id."' ");
while($rows = mysql_fetch_assoc($data))
{ 
 $db_id = $rows['id'];
 $array[] = array($db_id);
}

 foreach($array as $value)
 {
echo '<input type="radio" name="change" value="'.$value.'"><br>';
}

I am getting an error on the Radio line.

Array to string conversion

But when I print_r the array, the values are perfectly fetched and assigned in the array. What is the problem?

Answer 1

As Lashane mentioned to assign, a value on the array you need to use this syntax:

$array[] = $db_id;

http://www.php.net/manual/en/language.types.array.php

Answer 2

Problem is you are casting the id $row['id'] to an array before assigning it to the $array variable replace

$db_id = $rows['id'];
$array[] = array($db_id); //casting the value to an array here

with

$array[] = $rows['id'];

Should alleviate the issue. I guess to be more clear, you're not really casting, rather assigning a new array with the value of $row['id'] as its only value, none the less that is the issue.

Answer 3

Copy and paste following code :

 $data = mysql_query(" SELECT * FROM user_pokemon_db WHERE user_id='$id'");
    while($rows = mysql_fetch_assoc($data))
    { 
     $array[] = $rows['id'];
    }

     foreach($array as $value)
     {
      echo '<input type="radio" name="change" value="'.$value.'"><br>';
    }