How to get different output filename based on x86/x64 [closed]

StackOverflow https://stackoverflow.com/questions/23305415

Question

I am using VS2013 Express. I have my project setup to build in 32 or 64 bit, but I would like to get the .exe file when built, to include _32 or _64 depending on which platform I build for.

Not having any luck in the project properties.

Was it helpful?

Solution

Place the following into your post-build box in the "Build Events" section of the project's properties:

copy /Y "$(TargetDir)$(TargetFileName)" "$(TargetName)_$(PlatformName)$(TargetExt)"

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