MySQL Error - Not adding to database every time the query is called

Question

mysql_query("INSERT INTO accounting(transid, unixtime, username, description, amount, type, time) VALUES('$randomtransid', '0', '$yti', 'BLVD Offer Completion', '$theamount', 'points', '$dateandtime')");

The example code above is my MySQL query but it does not get added into the MySQL database every time I refresh the page...

What can I do?

============= SOLVED:

After adding "mysql_error();", this is the error:

Query failed: Duplicate entry ... for key 'uniqueness'

I fixed this by changing the structure of my database table.

Thanks

=============

Answer 1

You need a space after your table name. Otherwise it looks like a function.

mysql_query("INSERT INTO accounting(transid, unixtime, username, description, amount, type, time) VALUES('$randomtransid', '0', '$yti', 'BLVD Offer Completion', '$theamount', 'points', '$dateandtime')");
                                ^^^^^^^ 
                                  HERE

Should be:

mysql_query("INSERT INTO accounting (transid, unixtime, username, description, amount, type, time) VALUES('$randomtransid', '0', '$yti', 'BLVD Offer Completion', '$theamount', 'points', '$dateandtime')");

A few notes:

1. If you checked for error in your code you would have caught this quickly and easily. Always look for and handle errors. In your case a call to mysql_error() would have done the trick.

2. You shouldn't use mysql_* functions in new code. They are no longer maintained and are officially deprecated. See the red box? Learn about prepared statements instead, and use PDO, or MySQLi - this article will help you decide which. If you choose PDO, here is a good tutorial.

3. Since I can't see you handling this explicitly in your code I must assume you are wide open to SQL injections.