How to handle multiple input file arguments using getopts

Question

I'm trying to make script for multiple input data files. What is the best way, how to handle that arguments? Usage of script should be:

./script.sh -a sth -b sth - c sth -d sth input1 input2 input3    

I can handle parameters and arguments using getopts, but I have no idea, how to handle these input files, because there is no flag for them. Thanks

Answer 1

while getopts ":a:b:c:d:" opt; do
  case "$opt" in
    a) i=$OPTARG ;;
    b) j=$OPTARG ;;
    c) k=$OPTARG ;;
    d) l=$OPTARG ;;
  esac
done
shift $(( OPTIND - 1 ))


for file in "$@"; do
  # your stuff here
done

Please try this, this may solve the purpose for you

My own comment has prompted me to extend the answer:

In case you want to do it only from getopts: You will have to call the script as

./script -a hj -b op -c zx -d some -f "File in list seperated with spaces"

while getopts ":a:b:c:d:f:" opt; do
  case "$opt" in
    a) i=$OPTARG ;;
    b) j=$OPTARG ;;
    c) k=$OPTARG ;;
    d) l=$OPTARG ;;
    f) files=$OPTARG ;;
  esac
done
                      #no shift is required now, since we have file list in $files
for file in $files; do
  # your stuff here
done