After inspecting the images, I decided that a robust threshold will be more simple than anything. For example, looking at the C=40%, M=40% photo, I first inverted the intensities so black (the signal) will be white just using
im=(abs(255-im));
we can inspect its RGB histograms using this :
hist(reshape(single(im),[],3),min(single(im(:))):max(single(im(:))));
colormap([1 0 0; 0 1 0; 0 0 1]);
so we see that there is a large contribution to some middle intensity whereas the "signal" which is now white, is mostly separated to higher value. I then applied a simple thresholds as follows:
thr = @(d) (max([min(max(d,[],1)) min(max(d,[],2))])) ;
for n=1:size(im,3)
imt(:,:,n)=im(:,:,n).*uint8(im(:,:,n)>1.1*thr(im(:,:,n)));
end
imt=rgb2gray(imt);
and got rid of objects smaller than some typical area size
min_dot_area=20;
bw=bwareaopen(imt>0,min_dot_area);
imagesc(bw);
colormap(flipud(bone));
here's the result together with the original image:
The origin of this threshold is from this code I wrote that assumed sparse signals in the form of 2-D peaks or blobs in a noisy background. By sparse I meant that there's no pile up of peaks. In that case, when projecting max(image) on the x or y axis (by (max(im,[],1)
or (max(im,[],1)
you get a good measure of the background. That is because you take the minimal intensity of the max(im)
vector.
If you want to look at this differently you can look at the histogram of the intensities of the image. The background is supposed to be a normal distribution of some kind around some intensity, the signal should be higher than that intensity, but with much lower # of occurrences. By finding max(im)
of one of the axes (x or y) you discover what was the maximal noise level.
You'll see that the threshold picks that point in the histogram where there are still some noise above it, but ALL the signal is above it too. that's why I adjusted it to be 1.1*thr
. Last, there are many fancier ways to obtain a robust threshold, this is a quick and dirty way that in my view is good enough...