python key value list to panda series

Question

I have the following timeseries list in python:

list = [(datetime.datetime(2008, 7, 15, 15, 0), 0.134),
    (datetime.datetime(2008, 7, 15, 16, 0), 0.0),
    (datetime.datetime(2008, 7, 15, 17, 0), 0.0),
    (datetime.datetime(2008, 7, 15, 18, 0), 0.0),
    (datetime.datetime(2008, 7, 15, 19, 0), 0.0),
    (datetime.datetime(2008, 7, 15, 20, 0), 0.0),
    (datetime.datetime(2008, 7, 15, 21, 0), 0.0),
    (datetime.datetime(2008, 7, 15, 22, 0), 0.0),
    (datetime.datetime(2008, 7, 15, 23, 0), 0.0),
    (datetime.datetime(2008, 7, 16, 0, 0), 0.0)]

This list is a key value pair where key is datetime and value is the one after that separated by comma. I want to create pandas series from keys (datetime) and values (decimal value). Anyone can help me to split the above list of time series value into two list (list1 and list2) so I can creare the pandas Series object for further analysis from the following code?

import pandas as pd
ts = pd.Series(list1, list2)

Answer 1

In [34]: pd.Series(*zip(*((b,a) for a,b in data)))
Out[34]: 
2008-07-15 15:00:00    0.134
2008-07-15 16:00:00    0.000
2008-07-15 17:00:00    0.000
2008-07-15 18:00:00    0.000
2008-07-15 19:00:00    0.000
2008-07-15 20:00:00    0.000
2008-07-15 21:00:00    0.000
2008-07-15 22:00:00    0.000
2008-07-15 23:00:00    0.000
2008-07-16 00:00:00    0.000
dtype: float64

Or, eschewing the insane desire to make one-liners:

dates, vals = zip(*data)
s = pd.Series(vals, index=dates)

If the data is extremely long, you can avoid creating the intermediate tuples by using itertools.izip:

import itertools as IT
dates, vals = IT.izip(*data)
s = pd.Series(vals, index=dates)

Answer 2

You can use zip and splat to unpack your arguments as below.

import pandas as pd

my_list = [(datetime.datetime(2008, 7, 15, 15, 0), 0.134), 
        (datetime.datetime(2008, 7, 15, 16, 0), 0.0), 
        (datetime.datetime(2008, 7, 15, 17, 0), 0.0), 
        (datetime.datetime(2008, 7, 15, 18, 0), 0.0), 
        (datetime.datetime(2008, 7, 15, 19, 0), 0.0), 
        (datetime.datetime(2008, 7, 15, 20, 0), 0.0), 
        (datetime.datetime(2008, 7, 15, 21, 0), 0.0), 
        (datetime.datetime(2008, 7, 15, 22, 0), 0.0), 
        (datetime.datetime(2008, 7, 15, 23, 0), 0.0), 
        (datetime.datetime(2008, 7, 16, 0, 0), 0.0)]

ts = pd.Series(zip(*my_list))

zip(*my_list) effectively creates two tuples out of your data, one is a tuple of your datetime objects, one is your values. These two are then passed as the arguments to pd.Series.

Answer 3

Try

d = {}

for i in my_list:
    d[i[0]] = i[1]

s = pd.series (d)