C++ class implementation namespace

Question

I have files MyClass.hpp and MyClass.cpp

MyClass.hpp

class MyClass {
public:
    void method1();
    void method2();
};

MyClass.cpp

#include "MyClass.hpp"
void MyClass::method1() {
}

void MyClass::method2() {
}

I find it a little silly that I have to write out the MyClass:: every time I have to write a method implementation. Is there some sort of syntactic sugar that lets me just group all my implementation together?

Perhaps something like

namespace MyClass {
    void method1() {
    }

    void method2() {
    }
}

I don't mind using C++11 features, but I would like to stick with portable solutions.

EDIT:

I realize that the code above as written wouldn't work. I was just using it as an illustration of how I imagine some syntactic sugar would work to make things more convenient.

Answer 1

No, it is not possible.

The only way is to define your member functions directly inside the class definition, which makes them inline and may or may not be what you want.

Personally, I reckon having function definitions in source files is well worth having to type out a class name once in each.

Answer 2

No, there is no other-way. You have to repeat MyClass::

Answer 3

It is not possible to identify a method using namespace. In a namespace there can be several classes, non-member methods .... Since a class method can be defined in any source file (other than the header declaring the class itself), you have to specify which class a method belongs to while defining it.