You have to cast the void pointer to type: insert pointer.
int out = 0 ;
if( d->type == 10 )
out = (( insert* )d->info)->i ;
If statement is there to check what type Data is holding, otherwise you would be reading uninitialized memory.
Question
Excuse me, if it is kinda silly, but I can't get value of the structure element by it's pointer. What should i put after "out = " to get "5"?
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
typedef struct {
int type;
void* info;
} Data;
typedef struct {
int i;
char a;
float f;
double d;
} insert;
Data* insert_data(int t, void* s)
{
Data *d = (Data*)malloc(sizeof(Data));
d->type = t;
d->info = s;
return d;
}
int main()
{
Data *d;
int out;
insert in;
in.i = 5;
d = insert_data(10, &in);
out = /*some int*/
getch();
return 0;
}
Solution
You have to cast the void pointer to type: insert pointer.
int out = 0 ;
if( d->type == 10 )
out = (( insert* )d->info)->i ;
If statement is there to check what type Data is holding, otherwise you would be reading uninitialized memory.
OTHER TIPS
Assuming you want to access the newly created data and get it's value, you'll have to do a cast and access the element inside the struct, e.g.
insert* x = (insert*)(d->info);
out = x->i
Of course this is also doable in a one-liner:
out = ((insert*)(d->info))->i;