Show nearest locations from database to user's GeoLocation [closed]

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I am using Google Maps API v3 to show all stored locations from the database as a marker. What I am trying to do is show a list beneath the map with the closest locations(let's say within 10km) and their name, description & distance to user's current location, ordered by distance. I can't figure out how to build the query. I currently have this code which shows all places in the database:

$q = "SELECT name, image, description, price, lat, lng, rating, owner FROM places"; 
        $res1 = mysqli_query($linkNew, $q);

            while($row1 = mysqli_fetch_array($res1)){
                echo "<div class='place'>";
                echo "<h3 class='placeTitle'>" . $row1[0] . "</h2><br />";
                echo "<img src='" . $row1[1] . "' class='placeImage' width='30' height='30' />";    
                echo "<p class='placeDescription'>" .$row1[2] . "</p><br />";
                echo "<p class='placePrice'>€ " .$row1[3] . "/night</p><br />";
                echo "<p class='placeRating'>" .$row1[6] . "/5</p><br />";
                echo "<p class='placeOwner'>Owner: <a href='#'><b>" .$row1[7] . "</b></a></p><br />";
                echo "</div>";
            }       

Answer 1

$sql = "SELECT *, ( 3959 * acos( cos( radians(" . $lat . ") ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(" . $lng . ") ) + sin( radians(" . $lat . ") ) * sin( radians( lat ) ) ) ) AS distance FROM your_table HAVING distance < 5";

Where $lat and $lng are the coordinates of your center point, and lat/lng are your table columns. The above will list the locations within a 5 nm range. Replace 3959 by 6371 to change to kilometers.

This link could be useful: https://developers.google.com/maps/articles/phpsqlsearch_v3

To pick the user location:

if (navigator.geolocation) {

    navigator.geolocation.getCurrentPosition(function(position) {

        userLat = position.coords.latitude;
        userLng = position.coords.longitude;
    });
}