Note: this answer is for okhttp 1.x/2.x. For 3.x, see this other answer.
The class Multipart
from mimecraft encapsulates the whole HTTP body and can handle regular fields like so:
Multipart m = new Multipart.Builder()
.type(Multipart.Type.FORM)
.addPart(new Part.Builder()
.body("value")
.contentDisposition("form-data; name=\"non_file_field\"")
.build())
.addPart(new Part.Builder()
.contentType("text/csv")
.body(aFile)
.contentDisposition("form-data; name=\"file_field\"; filename=\"file1\"")
.build())
.build();
Take a look at examples of multipart/form-data encoding to get a sense of how you need to construct the parts.
Once you have a Multipart
object, all that's left to do is specify the right Content-Type
header and pass on the body bytes to the request.
Since you seem to be working with the v2.0 of the OkHttp API, which I don't have experience with, this is just guess code:
// You'll probably need to change the MediaType to use the Content-Type
// from the multipart object
Request.Body body = Request.Body.create(
MediaType.parse(m.getHeaders().get("Content-Type")),
out.toByteArray());
For OkHttp 1.5.4, here is a stripped down code I'm using which is adapted from a sample snippet:
OkHttpClient client = new OkHttpClient();
OutputStream out = null;
try {
URL url = new URL("http://www.example.com");
HttpURLConnection connection = client.open(url);
for (Map.Entry<String, String> entry : multipart.getHeaders().entrySet()) {
connection.addRequestProperty(entry.getKey(), entry.getValue());
}
connection.setRequestMethod("POST");
// Write the request.
out = connection.getOutputStream();
multipart.writeBodyTo(out);
out.close();
// Read the response.
if (connection.getResponseCode() != HttpURLConnection.HTTP_OK) {
throw new IOException("Unexpected HTTP response: "
+ connection.getResponseCode() + " " + connection.getResponseMessage());
}
} finally {
// Clean up.
try {
if (out != null) out.close();
} catch (Exception e) {
}
}