If you want to use the same figure created by pandas
you cannot create a new one (see below). You can set the ticks positions manually adding plt.xticks()
after the plt.xlim()
plt.xticks(seq)
where the sequence seq
can be pd.np.linspace(1, 35086, 5)
for example, or given manually like:
seq = [1, 10000, 20000, 35086]
The final code would be:
import pandas as pd
import matplotlib.pyplot as plt
a = [583, 1379, 1404, 5442, 5512, 5976, 5992, 6111, 6239, 6375, 6793, 6994, 7109, 7149, 7210, 7225, 7459, 8574, 9154, 9417, 9894, 10119, 10355, 10527, 11933, 12170, 12172, 12273, 12870, 13215, 13317, 13618, 13632, 13790, 14260, 14282, 14726, 15156, 19262, 21501, 21544, 21547, 21818, 21939, 22386, 22622, 22830, 23898, 25796, 26126, 26340, 28585, 28645, 28797, 28808, 28878, 29167, 29168, 31161, 31225, 32284, 32332, 32641, 33227, 34175, 34349, 34675, 34772, 34935, 35086]
d = pd.DataFrame(a)
d.hist(bins=50)
ax = plt.gca()
ax.set_xlabel("xTEST")
ax.set_ylabel("yTEST")
plt.subplots_adjust(bottom=.25, left=.25)
plt.ticklabel_format(style = 'plain')
ax.set_title('Title here!', color='black')
ax.set_xlim(xmin=1, xmax=35086)
ax.set_xticks(pd.np.linspace(1, 35086, 5))
plt.show()
Giving: