Difference between 08 and 8 in for int variable in java [duplicate]

StackOverflow https://stackoverflow.com/questions/23534851

  •  17-07-2023
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Question

I have declared a variable int i = 08; I got an error in netbeans that "integer number too large"! Can anyone explain why this happens. I am coding in Java. 

for (int i = 08; l <= Integer.parseInt(dd); i++)

To remove the error I then tried int i = 8 which works; Now I do not understand that why int i = 08 do not work?

Was it helpful?

Solution

Literal integer types starting at 0 are interpreted as octal base. Octal base doesn't allow 8, only digits from 0 to 7.

OTHER TIPS

If you write '0' as leading it indicate Octal

Leading 0 suggests 8-based number system, so viable digits there are 0 - 7

The prefix "0" indicates "octal", and 8 is larger than the maximum-sized octal digit.

The prefix 0 indicates octal(8 base)(digits 0-7).

public class MainClass{

  public static void main(String[] argv){

    int intValue = 034;  // 28 in decimal
    int six = 06; // Equal to decimal 6
    int seven = 07; // Equal to decimal 7
    int eight = 010; // Equal to decimal 8
    int nine = 011; // Equal to decimal 9

    System.out.println("Octal 010 = " + eight);

  }

}
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