First thing I'd like to point out the wrong thing you are doing is you are writing the same jQuery function twice at different positions in your code. This is an unnecessary code redundancy. It's a very bad style of programming. If you write the function in following fashion you will get everything working fine. Also remove the same function code you have written in AJAX response.
$(function () {
$(document).delegate('.products','click',function (e) {
var table_id = $(this).closest('table').attr('id');
var no = table_id.match(/\d+/)[0];
//var first_row = $(this).closest('table').find('tbody tr:first').attr('id');
var first_row = $('#'+table_id).find('tbody tr:first').attr('id');
var new_row = $('#'+first_row).clone();
//var tbody = $('tbody', '#'+table_id);
var tbody = $('#' + table_id + ' tbody');
var n = $('tr', tbody).length + 1;
new_row.attr('id', 'reb' + no +'_'+ n);
$(':input', new_row).not('.prod_list').remove();
$('select', new_row).attr('name','product_id_'+no+'['+n+']');
$('select', new_row).attr('id','product_id_'+no+'_'+n);
$('<button style="color:#C00; opacity: 2;" type="button" class="close delete" data-dismiss="alert" aria-hidden="true">×</button>').appendTo( $(new_row.find('td:first')) );
tbody.append(new_row);
$('.delete').on('click', deleteRow);
});
});