Here's one way to do it:
$ A=(1 2 3 4); B=(a b c d); for i in $(seq 0 3); do echo ${A[$i]}${B[$i]}; done
1a
2b
3c
4d
Question
It sounds simple but I can't do it in a simple way. In shell for loop, two vars
A=" 1 2 3 4"
B=" a b c d"
, try to print 1a 2b 3c 4d. Tried
A=" 1 2 3 4"
B=" a b c d"
for m in $A
for n in $B;
do echo $m$n done
.
The output is
1
2
3
4
5
for
l
in
a
b
c
d
e
Anyone can help this out?
Solution
Here's one way to do it:
$ A=(1 2 3 4); B=(a b c d); for i in $(seq 0 3); do echo ${A[$i]}${B[$i]}; done
1a
2b
3c
4d
OTHER TIPS
In your attempt, the for cases aren't closed with a ;, so it keeps interpreting words in your second for statement as cases for the first for statement.
Use instead:
A="1 2 3 4"
B="a b c d"
for m in $A ; do
for n in $B ; do
echo $m$n
done
done