A list
could contain list
elements as well. So you can just use the same approach for multiple constants:
cval <- 1:10
l <- vector(mode = "list", length = length(cval)
for (i in seq(along=cval)) {
l[[i]] <- list(function1name(df, cval=cval[i]))
}
Or you could use lapply
:
cval <- 1:10
l <- lapply(cval, function1name, df = df)